keep format Follow
is there any way so when i copy and paste my code stays the same ?
my code:
$this->DB->build( array( 'select' => 't.*', 'from' => array( 'credits_trans_log' => 't' ), 'add_join' => array( 0 => array( 'select' => 'mf.member_id as from_id, mf.members_display_name as from_name, mf.members_seo_name as from_seo', 'from' => array( 'members' => 'mf'), 'where' => 't.t_from=mf.member_id', 'type' => 'left' ), 1 => array( 'select' => 'mt.member_id as to_id, mt.members_display_name as to_name, mt.members_seo_name as to_seo', 'from' => array( 'members' => 'mt'), 'where' => 't.t_to=mt.member_id', 'type' => 'left' ) ), 'order' => 't.t_date DESC', 'limit' => array( 0, 10 ) ) );
but then if if i copy and paste it looks like this bellow and i dont wan't to lose the format from above:
$this->DB->build( array( 'select' => 't.*', 'from' => array( 'credits_trans_log' => 't' ), 'add_join' => array( 0 => array( 'select' => 'mf.member_id as from_id, mf.members_display_name as from_name, mf.members_seo_name as from_seo', 'from' => array( 'members' => 'mf'), 'where' => 't.t_from=mf.member_id', 'type' => 'left' ), 1 => array( 'select' => 'mt.member_id as to_id, mt.members_display_name as to_name, mt.members_seo_name as to_seo', 'from' => array( 'members' => 'mt'), 'where' => 't.t_to=mt.member_id', 'type' => 'left' ) ), 'order' => 't.t_date DESC', 'limit' => array( 0, 10 ) ) );
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Hello,
do you use tabs for indents? If yes, check your settings (Preferences > Code Stype > PHP). You should have:
Use tab character NOT checked
Tab size: 4
Indent: 4
Continuation indent: 4
Good luck.
Hi there,
Settings | Editor | Smart Keys --> Reformat on paste = None
thank you, that worked :)