Sub-process stdout using file object not working when using PyCharm

I have a simple snippet of Python program which correctly works using IDLE or Windows's CMD. But I am not able to make it work using PyCharm. The goal is to run nc.exe (to get logs from a device under test) using subprocess.Popen and to redirect the sub-process stdout to a log file. Below is the python code:

import subprocess

nc_ex = r"C:\Users\lambda\Desktop\Tool\nc.exe"
ipaddr = "192.168.51.202"
port = "3001"
log_file = open("test_file.bin", "wb")
p = subprocess.Popen([nc_ex, ipaddr, port], stdout=log_file)

Using IDLE or CMD, the log file is correctly growing with logs received. Using PyCharm the log file remains empty. I tried to deal with subprocess.Popen arguments value (creationflags=subprocess.CREATE_NEW_CONSOLE), look for Pycharm configuration, follow this topic subprocess not working when running inside pycharm , but I can't figure it out. Does anyone has a solution to this strange behavior?

Thanks.