NSUInteger - unsigned long or unsigned int?

Permanently deleted user

创建于 2011年05月25日 09:50

Hi,

I am doing most of my iOS code in AppCode these days (thank you again JetBrains for this wonderful, intelligent editor and debugger), but as I work on a project with some xib-files and a CoreData model, I have to dive into Xcode frequently. I have just noticed that if I have code like this:


NSUInteger hg2g = 42;
NSLog(@"The answer is: %d", hg2g);

AppCode says: "Format specifier '%d' requires the type 'int' instead of 'NSUInteger'..."

Then I fix it by changing it to:


NSUInteger hg2g = 42;
NSLog(@"The answer is: %lu", hg2g);

Then I go into Xcode which says: "Conversion specifies type 'unsigned long' but the argument has type 'NSUInteger' (aka 'unsigned int')

Fix-it in Xcode "repairs" it to:

NSUInteger hg2g = 42;
NSLog(@"The answer is: %u", hg2g);

And now AppCode of course says: "Format specifier '%u' requires the type 'unsigned int' instead of 'NSUInteger'..."

Which is right?

NSUInteger is defined in the "NSObjCRuntime.h" file:

#if __LP64__ || (TARGET_OS_EMBEDDED && !TARGET_OS_IPHONE) || TARGET_OS_WIN32 || NS_BUILD_32_LIKE_64
typedef long NSInteger;
typedef unsigned long NSUInteger;
#else
typedef int NSInteger;
typedef unsigned int NSUInteger;
#endif

1 条评论

Alexander Kirillin

创建于 2011年05月25日 11:23

Filed an issue:
http://youtrack.jetbrains.net/issue/OC-941

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