Maven - reading effective POM via Maven library

Hi everybody,

in order to get the right configurations for my plugin I need to read from the effective POM of the working project. 
I found the class MavenShowEffectivePom under org.jetbrains.idea.maven.project.actions which seems to do exactly what I need. 

I tried to implement the code they use and I've ran into a problem I can't seem to solve. 

In order to get the mavenProject they use:

MavenProjectsManager manager = MavenProjectsManager.getInstance(project);
MavenProject mavenProject = manager.findProject(file);

I've implemented those lines and made sure to generate project and file exactly as they do it:

public void actionPerformed(@NotNull AnActionEvent event) {
    Project project = MavenActionUtil.getProject(event.getDataContext());
    if(project != null) {
        VirtualFile file = findPomXml(event.getDataContext());
        if(file != null) {
            if(MavenServerManager.getInstance().isUseMaven2()) {
                showUnsupportedNotification(project);
            } else {
                actionPerformed(project, file);
            }

        }
    }
}

Now when I try to build my project it throws this error:

Error:(26, 44) java: cannot access org.jetbrains.idea.maven.model.MavenArtifact
class file for org.jetbrains.idea.maven.model.MavenArtifact not found

Which points to manager.findProject(file)

In addition to this it also throws this error:

Error:(36, 66) java: cannot access org.jetbrains.idea.maven.model.MavenId
class file for org.jetbrains.idea.maven.model.MavenId not found

at:

String fileName = mavenProject.getMavenId() + "-effective-pom.xml";

This is everything in the stacktrace. I don't understand why it even needs to access the org.jetbrains.idea.maven.model part since the

manager.findProject(file);

is from the org.jetbrains.idea.maven.project directory which does exist!

Can anybody help me or point me into the right direction?