How to get a XmlFile from a PsiFile

If you are doing a lot of DOM work, you may wish to check out the DOM API here http://confluence.jetbrains.com/display/IDEADEV/Accessing+XML+through+IntelliJ+IDEA+DOM
You should also check out the IDEA Architecture here http://confluence.jetbrains.com/display/IDEADEV/IntelliJ+IDEA+Architectural+Overview - which contains this information

Give the documentation a read to find your answer, and if you're still having issues just ask! :)

The first link is what I was using to get as far as I did, but every place they get the XmlFile they just have "...".

But I think the 2nd link is helping me out, but still having some issues. This is what I have:

Project project = e.getData(PlatformDataKeys.PROJECT);
        PsiFile psiFile = e.getData(LangDataKeys.PSI_FILE);
        Editor editor = e.getData(PlatformDataKeys.EDITOR);
        if(psiFile == null || editor == null) {
             FileViewProvider viewProvider = psiFile.getViewProvider();
             XmlFile xmlFile = (XmlFile) viewProvider.getPsi(StdLanguages.XML);
        }

When I'm debugging, xmlFile is null. One thing I should point out is my file is not actually a .xml file extension. It's a custom extension (example file.test) that really just contains an xml tree. This cannot be changed.

You should register a file type provider, which can associate your file extension to the XmlFile type --

• Update your plugin.xml to use the fileTypeFactory extension point

          <fileTypeFactory implementation="foo.bar.YourFactory"/>

• Your class should extend fileTypeFactory and provide a method for createFileTypes

  def createFileTypes(consumer: FileTypeConsumer) =
    consumer.consume(XmlFileType.INSTANCE, "YourFileExtension")
Your file extension should now be associated with an Xml file type


• Update your action - you should be able to treat your file as XML

    public void actionPerformed(AnActionEvent e) {
        PsiFile psiFile = e.getData(LangDataKeys.PSI_FILE);
        if(psiFile != null && psiFile.getFileType() == StdFileTypes.XML) {
            XmlFile xmlFile = (XmlFile) psiFile;
            // ... System.out.println("Opened Xml file " + xmlFile.getText());
        }
    }